Dimethylformamide → Benzamide

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Reaction Steps

Ester compound 3 is converted to the free carboxylic acid, and is then reacted with substituted aniline compound 4 to yield an arylamide of formula 5. For example, LiOH is added to a stirred solution of 3 in a mixture of solvents. The volatiles are removed under vacuum, and the residue is diluted with water and acidified to about pH 3. The resulting solids are filtered, washed with water and dried under vacuum to furnish a carboxylic acid intermediate. The intermediate is dissolved in a solvent such as DMF and the mixture is stirred to prepare a solution. To the stirred solution is added 1-ethyl-3-(3′-dimethylaminopropyl)carbodiimide hydrochloride (EDCI) followed by hydroxybenzotriazole (HOBt). After stirring, diisopropyl ethyl amine is added and stirred. Then substituted aniline 4 (representative of substituted aryl or heteroaryl) is added, and the reaction mixture is stirred. The solvent is removed under vacuum. The residue is diluted with water and stirred. The resulting solids are filtered and purified through column chromatography to provide benzamide compound 5.

Provenance & Evidence