Stearic Acid → Cyclododeca-1,3,5-triene
Reaction equation
[CH:1]1[CH2:12][CH2:11][CH:10]=[CH:9][CH2:8][CH2:7][CH:6]=[CH:5][CH2:4][CH2:3][CH:2]=1.C(O)(=O)CCCCCCCCCCCCCCCCC.[OH-].[K+]>O>[CH:5]1[CH2:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH:12]=[CH:1][CH:2]=[CH:3][CH:4]=1Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
A 600 mL beaker was charged with 150 g deionized water, 100 g of 91% pure 1,5,9-cyclododecatriene and 5.0 g of stearic acid. The resulting mixture was heated to 75°-80° C. to melt stearic acid and was intensively mixed at this temperature using a high shear Tekmar agitator while adding sufficient 50% aq. KOH to raise the pH to 10.5-11.0. The emulsion was cooled to room temperature and allowed to stand overnight. (Note: density differences between bulk water and emulsified particles caused some separation overnight, but gentle mixing again gave a uniform emulsion). The final emulsion contained 39.2 percent 1,5,9-cyclododecatriene (I) by weight.
Workup
- additionA 600 mL beaker was charged with 150 g
- temperatureThe resulting mixture was heated to 75°-80° C.
- additionwas intensively mixed at this temperature
- temperatureto raise the pH to 10.5-11.0
- customsome separation overnight
- additiongentle mixing again
- customgave a uniform emulsion)
Sources & evidence
- ORD record
- ord-4641f6233658400fa8dd804992806993
- Source dataset
- uspto-grants-1993_10
- Patent number
- US05254761
Reaction notes
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