HRID1662640

反应详情

EQUATION

反应方程式

HRID 1662640 的结构方程式

PROCEDURE

实验过程

With 290 mg of 5-chloro-3-(2-methoxyphenyl)-3-[2-oxo-2-(4-pyridin-4-yl piperidin-1-yl)ethyl]-1,3-dihydro-2H-indol-2-one obtained in Step 51-2 and 195 mg of 2-methoxy-4-(trifluoromethoxy)benzene sulfonyl chloride as starting materials, 173 mg of the title compound (colorless amorphous) was obtained by a similar method to Example 1.