HRID1669514

反应详情

EQUATION

反应方程式

HRID 1669514 的结构方程式

PROCEDURE

实验过程

The title compound was prepared from the product from step 2 (1.3 g, 2.2 mmol) and NaOH (0.2 g, 4.4 mmol) using the Step 7 procedure of example 1 with 99% yield (1.0 g). 1HNMR (CDCl3) δ 1.43 (s, 9H), 3.86 (s, 2H), 4.71 (br, 1H), 4.93 (br, 1H), 5.76 (br, 1H), 6.75 (m, 4H), 7.02 (d, J=6.8 Hz, 2H), 7.13 (m, 3H), 7.23 (m, 4H), MS m/z 432 (M−1).