HRID1669581

反应详情

EQUATION

反应方程式

HRID 1669581 的结构方程式

PROCEDURE

实验过程

The title compound was prepared from 4-hydroxy-2-(4-isopropylthiazol-2-yl)-7-methoxyquinoline, oct-7-enoic acid and intermediate 5 following the procedure (Step D-H) reported for 18-[2-[4-(isopropyl)thiazol-2-yl]-7-methoxyquinolin-4-yloxy]-2,15-dioxo-3,16-diazatricyclo[14.3.0.04,6]nonadec-7-ene-4-carboxylic acid 10: m/z=619 (M+H)+.