Sodium Hydroxide → 6-Morpholino-6-oxohexanoic acid
Reaction equation
[N:1]1([C:7](=[O:16])[CH2:8][CH2:9][CH2:10][CH2:11][C:12]([O:14]C)=[O:13])[CH2:6][CH2:5][O:4][CH2:3][CH2:2]1.[OH-].[Na+]>CO.O>[N:1]1([C:7](=[O:16])[CH2:8][CH2:9][CH2:10][CH2:11][C:12]([OH:14])=[O:13])[CH2:2][CH2:3][O:4][CH2:5][CH2:6]1Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
Methyl 6-morpholin-4-yl-6-oxohexanoate (4.60 g) obtained in Reference Example 84(1) is dissolved in methanol (20 ml), and thereto is added a solution of sodium hydroxide (1.61 g) in water (8 ml). The mixture is stirred at room temperature for 19 hours. The reaction solution is concentrated under reduced pressure and the residue is neutralized with 2 N hydrochloric acid. The residue is concentrated under reduced pressure and extracted with chloroform. The organic layer is dried over sodium sulfate and the solvent is concentrated under reduced pressure to give the title compound (4.11 g).
Workup
- concentrationThe reaction solution is concentrated under reduced pressure
- concentrationThe residue is concentrated under reduced pressure
- extractionextracted with chloroform
- dry with materialThe organic layer is dried over sodium sulfate
- concentrationthe solvent is concentrated under reduced pressure
Sources & evidence
- ORD record
- ord-98820bb8e0334c53b7e207e3ed04c5d6
- Source dataset
- uspto-grants-2010_06
- Patent number
- US07737161B2
Reaction notes
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