HRID1680697

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID7918

Acetic anhydride

C4H6O3

结构：CCn1c(C)c(C(=O)c2ncccc2C(=O)O)c2ccccc21

HCID112344

3-Pyridinecarboxylic acid, 2-[(1-ethyl-2-methyl-1H-indol-3-yl)carbonyl]-

C18H16N2O3

HCID12747344

未命名化合物

PRODUCTS

生成物

结构：CCn1c(C)c(C2(c3c(-c4ccccc4)c(-c4ccccc4)c4ccccn34)OC(=O)c3cccnc32)c2ccccc21

HCID20536954

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID6212

Chloroform

CHCl3

PROCEDURE

实验过程

A mixture of 1.6 grams of (1-ethyl-2-methylindol-3-yl) (3-carboxy-pyridin-2-yl)ketone, 1.85 grams of 1,2-diphenylindolizine and 10 ml. of acetic anhydride was heated at about 40° C. for 104 minutes and then cooled in an ice bath. The reaction mixture was filtered and the product was repeatedly recrystallized from a toluene-petroleum ether mixture until a constant melting point of 206.5°-207.5° C. was obtained. A chloroform solution of the final product produced a blue color when applied to a record sheet material coated with a zinc-modified phenolic resin.

WORKUP

后处理

temperaturecooled in an ice bath
filtrationThe reaction mixture was filtered
customthe product was repeatedly recrystallized from a toluene-petroleum ether mixture until a constant melting point of 206.5°-207.5° C.
customwas obtained

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-f1e1e6d530a844fb91e1cf1f62e263cc
来源数据集: uspto-grants-1981_06
DOI: 10.6084/m9.figshare.5104873.v1
专利: US04275206
来源说明: uspto-grants-1981_06

反应 SMILES

[CH2:1]([N:3]1[C:11]2[C:6](=[CH:7][CH:8]=[CH:9][CH:10]=2)[C:5]([C:12]([C:14]2[C:19]([C:20]([OH:22])=[O:21])=[CH:18][CH:17]=[CH:16][N:15]=2)=O)=[C:4]1[CH3:23])[CH3:2].[C:24]1([C:30]2[C:31]([C:39]3[CH:44]=[CH:43][CH:42]=[CH:41][CH:40]=3)=[CH:32][N:33]3[C:38]=2[CH:37]=[CH:36][CH:35]=[CH:34]3)[CH:29]=[CH:28][CH:27]=[CH:26][CH:25]=1.C(OC(=O)C)(=O)C>C(Cl)(Cl)Cl>[CH2:1]([N:3]1[C:11]2[C:6](=[CH:7][CH:8]=[CH:9][CH:10]=2)[C:5]([C:12]2([C:32]3[N:33]4[C:38]([CH:37]=[CH:36][CH:35]=[CH:34]4)=[C:30]([C:24]4[CH:29]=[CH:28][CH:27]=[CH:26][CH:25]=4)[C:31]=3[C:39]3[CH:40]=[CH:41][CH:42]=[CH:43][CH:44]=3)[C:14]3=[N:15][CH:16]=[CH:17][CH:18]=[C:19]3[C:20](=[O:21])[O:22]2)=[C:4]1[CH3:23])[CH3:2]