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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1684313Generated: October 29, 2026

Potassium Iodide → 2-Fluoro-4-chloro-5-(3-methylcyclopentyl)oxyaniline

https://huagongshe.com/reaction/1684313

Reaction equation

Participants

RoleNameHCIDCharge
ReactantPotassium IodideHCID 4875—
ReactantSodium HydroxideHCID 14798—
Reactant5-Amino-2-chloro-4-fluorophenolHCID 158654—
Reactant3-Methylcyclopentyl 4-methylbenzene-1-sulfonateHCID 19042338—
CatalystTetrabutylammonium BromideHCID 74236—
SolventWaterHCID 962—
SolventTolueneHCID 1140—
Product2-Fluoro-4-chloro-5-(3-methylcyclopentyl)oxyanilineHCID 1527939142.9%

Reaction Conditions

Temperature100 °C

Reaction Steps

A round-bottomed flask (200 cc) equipped with a mechanical stirrer was charged with 5-amino-2-chloro-4-fluorophenol (3.00 g, 18.6 mmol), 3-methylcyclopentyl p-toluenesulfonate (4.60 g, 18.6 mmol), tetrabutylammonium bromide (300 mg, 0.93 mmol) and potassium iodide (300 mg, 1.81 mmol) to prepare a solution in toluene (30 mL). Subsequently, 48% sodium hydroxide in aqueous solution (30 mL) was added slowly and the mixture was stirred under heating at 100° C. for 48 h. After completion of the reaction, the reaction mixture was cooled to room temperature and water (50 mL) was added, followed by extraction with ethyl acetate (30 mL×3). The organic layers were combined, washed with water (10 mL) and saturated brine (10 mL) and dried with anhydrous magnesium sulfate. After the desiccant was removed, the solvent was distilled off under vacuum to give 2-fluoro-4-chloro-5-(3-methylcyclopentyloxy)aniline (1.94 g, 7.96 mmol; yield=42.9%) as a brown oil. 1H-NMR(CDCl3,TMS,ppm): δ1.02 and 1.10(total 3H, each d,J=6.0Hz), 1.22-2.58(7H,m), 3.75(2H,brs), 4.65(1H,m), 6.33(1H,d,JHF =8.0Hz), 6.98(1H,d,JHF =10.0Hz)

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05639915
Source datasetuspto-grants-1997_06
ORD IDord-612bd0831ddb4691bee967cf2f4d32a5
Source noteuspto-grants-1997_06