HRID1685850

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID15765418

Cyclopropanesulfonamide

C3H7NO2S

结构：CCc1c(OC)ccc2c(OC3CC4C(=O)NC5(C(=O)O)CC5C=CCCCCN(C)C(=O)C4C3)cc(-c3nc(C(C)C)cs3)nc12

HCID66871155

未命名化合物

结构：COc1ccc2c(OC3CC4C(=O)NC5(C(=O)NS(=O)(=O)C6CC6)CC5C=CCCCCN(C)C(=O)C4C3)cc(-c3nc(C(C)C)cs3)nc2c1Cl

HCID66903073

未命名化合物

PRODUCTS

生成物

结构：CCc1c(OC)ccc2c(OC3CC4C(=O)NC5(C(=O)NS(=O)(=O)C6CC6)CC5C=CCCCCN(C)C(=O)C4C3)cc(-c3nc(C(C)C)cs3)nc12

HCID66870825

未命名化合物

PROCEDURE

实验过程

The title compound was prepared from 17-[8-ethyl-2-(4-isopropylthiazole-2-yl)-7-methoxyquinolin-4-yloxy]-13-methyl-2,14-dioxo-3,13-diazatricyclo[13.3.0.04,6]-octadec-7-ene-4-carboxylic acid (70) and cyclopropylsulfonamide following the procedure reported for the preparation of N-[17-[8-chloro-2-(4-isopropylthiazole-2-yl)-7-methoxyquinolin-4-yloxy]-13-methyl-2,14-dioxo-3,13-diazatricyclo[13.3.0.04,6]-octadec-7-ene-4-carbonyl](cyclopropyl)sulfonamide (56): m/z=764 (M+H)+.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-655811fc62de499a8a2e6de5c2057c92
来源数据集: uspto-grants-2012_04
DOI: 10.6084/m9.figshare.5104873.v1
专利: US08148399B2
来源说明: uspto-grants-2012_04

反应 SMILES

[CH2:1]([C:3]1[C:4]([O:46][CH3:47])=[CH:5][CH:6]=[C:7]2[C:12]=1[N:11]=[C:10]([C:13]1[S:14][CH:15]=[C:16]([CH:18]([CH3:20])[CH3:19])[N:17]=1)[CH:9]=[C:8]2[O:21][CH:22]1[CH2:39][CH:38]2[CH:24]([C:25](=[O:45])[N:26]([CH3:44])[CH2:27][CH2:28][CH2:29][CH2:30][CH:31]=[CH:32][CH:33]3[C:35]([C:41]([OH:43])=O)([NH:36][C:37]2=[O:40])[CH2:34]3)[CH2:23]1)[CH3:2].[CH:48]1([S:51]([NH2:54])(=[O:53])=[O:52])[CH2:50][CH2:49]1.ClC1C(OC)=CC=C2C=1N=C(C1SC=C(C(C)C)N=1)C=C2OC1CC2C(C(=O)N(C)CCCCC=CC3C(C(NS(C4CC4)(=O)=O)=O)(NC2=O)C3)C1>>[CH2:1]([C:3]1[C:4]([O:46][CH3:47])=[CH:5][CH:6]=[C:7]2[C:12]=1[N:11]=[C:10]([C:13]1[S:14][CH:15]=[C:16]([CH:18]([CH3:20])[CH3:19])[N:17]=1)[CH:9]=[C:8]2[O:21][CH:22]1[CH2:39][CH:38]2[CH:24]([C:25](=[O:45])[N:26]([CH3:44])[CH2:27][CH2:28][CH2:29][CH2:30][CH:31]=[CH:32][CH:33]3[C:35]([C:41]([NH:54][S:51]([CH:48]4[CH2:50][CH2:49]4)(=[O:53])=[O:52])=[O:43])([NH:36][C:37]2=[O:40])[CH2:34]3)[CH2:23]1)[CH3:2]