Dimethylformamide → 4-Diethylamino-3-isopropylbenzaldehyde

Participants

Reaction Steps

In a manner analogous to example 1 d, the process is carried out by a reaction of 1.8 ml (4.4 mmol) of 2.5M n-butyllithium/hexane with 1 g (3.7 mmol) of (4-bromo-2-isopropylphenyl)diethylamine and 0.35 ml (4.5 mmol) of dimethylformamide. 790 mg of 4-diethylamino-3-isopropylbenzaldehyde are obtained in the form of a yellow oil (yield=97%).

Provenance & Evidence