HRID1707277

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID5238

Sodium Iodide

INa

HCID3047504

Piperidine, 4,4-diphenyl-, hydrochloride

C17H20ClN

结构：CC(=O)C1=C(C)NC(C)=C(C(=O)CCCCCBr)C1c1cccc([N+](=O)[O-])c1

HCID18962945

未命名化合物

PRODUCTS

生成物

结构：CC(=O)C1=C(C)NC(C)=C(C(=O)CCCCCN2CCC(c3ccccc3)(c3ccccc3)CC2)C1c1cccc([N+](=O)[O-])c1.Cl

HCID18962995

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID6342

Acetonitrile

C2H3N

PROCEDURE

实验过程

9 g (20 mmol) 5-acetyl-1,4-dihydro-2,6-dimethyl-3-(6-bromohexanoyl)4-(3-nitrophenyl) -pyridine are reacted first with 6 g (40 mmol) sodium iodide, as described for starting compound B, and then with 11 g (38 mmol) 4,4-diphenylpiperidine hydrochloride. Working up is carried out as described for starting compound B. The crude product is chromatographed with toluene/acetone=1/1. The product thus obtained is taken up in 20 ml acetonitrile. The title compound is precipitated by addition of ethereal hydrochloric acid. Yield: 4 g (31%). M.p. 136° C. decomp. (acetonitrile).

WORKUP

后处理

customThe crude product is chromatographed with toluene/acetone=1/1
customThe product thus obtained
customThe title compound is precipitated by addition of ethereal hydrochloric acid

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-aa7536cbd6fb4642ad430f218727c3f4
来源数据集: uspto-grants-1994_10
DOI: 10.6084/m9.figshare.5104873.v1
专利: US05352684
来源说明: uspto-grants-1994_10

反应 SMILES

[C:1]([C:4]1[CH:5]([C:20]2[CH:25]=[CH:24][CH:23]=[C:22]([N+:26]([O-:28])=[O:27])[CH:21]=2)[C:6]([C:12](=[O:19])[CH2:13][CH2:14][CH2:15][CH2:16][CH2:17]Br)=[C:7]([CH3:11])[NH:8][C:9]=1[CH3:10])(=[O:3])[CH3:2].[I-].[Na+].[ClH:31].[C:32]1([C:38]2([C:44]3[CH:49]=[CH:48][CH:47]=[CH:46][CH:45]=3)[CH2:43][CH2:42][NH:41][CH2:40][CH2:39]2)[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=1>C(#N)C>[ClH:31].[C:1]([C:4]1[CH:5]([C:20]2[CH:25]=[CH:24][CH:23]=[C:22]([N+:26]([O-:28])=[O:27])[CH:21]=2)[C:6]([C:12](=[O:19])[CH2:13][CH2:14][CH2:15][CH2:16][CH2:17][N:41]2[CH2:42][CH2:43][C:38]([C:32]3[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=3)([C:44]3[CH:49]=[CH:48][CH:47]=[CH:46][CH:45]=3)[CH2:39][CH2:40]2)=[C:7]([CH3:11])[NH:8][C:9]=1[CH3:10])(=[O:3])[CH3:2]