HRID1707281

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID5238

Sodium Iodide

INa

HCID3047504

Piperidine, 4,4-diphenyl-, hydrochloride

C17H20ClN

结构：CC(=O)C1=C(C)NC(CCCCCCBr)=C(C(C)=O)C1c1cccc([N+](=O)[O-])c1

HCID18962993

未命名化合物

PRODUCTS

生成物

结构：CC(=O)C1=C(C)NC(CCCCCCN2CCC(c3ccccc3)(c3ccccc3)CC2)=C(C(C)=O)C1c1cccc([N+](=O)[O-])c1.Cl

HCID18962947

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID3283

Diethyl Ether

C4H10O

溶剂HCID6342

Acetonitrile

C2H3N

PROCEDURE

实验过程

3.5 g (7.8 mmol) 3,5-diacetyl-1,4-dihydro-2-(6-bromohexyl)6-methyl-4-(3-nitrophenyl) -pyridine are reacted first with 2.3 g (15.6 mmol) sodium iodide, as described for starting compound B, and then with 4.3 g (15.6 mmol)4,4-diphenylpiperidine hydrochloride. Working up is carried out as described for starting compound B. The crude product is chromatographed with toluene/acetone=8/2. The product thus obtained is taken up in 5 ml acetonitrile and the mixture is diluted with 5 ml diethyl ether. The title compound is precipitated by addition of ethereal hydrochloric acid. Yield: 3 g (61%). M.p. 166°-167° C. (acetonitrile).

WORKUP

后处理

customThe crude product is chromatographed with toluene/acetone=8/2
customThe product thus obtained
customThe title compound is precipitated by addition of ethereal hydrochloric acid

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-a652cdc2ab294636966117f50f8f219b
来源数据集: uspto-grants-1994_10
DOI: 10.6084/m9.figshare.5104873.v1
专利: US05352684
来源说明: uspto-grants-1994_10

反应 SMILES

[C:1]([C:4]1[CH:9]([C:10]2[CH:15]=[CH:14][CH:13]=[C:12]([N+:16]([O-:18])=[O:17])[CH:11]=2)[C:8]([C:19](=[O:21])[CH3:20])=[C:7]([CH3:22])[NH:6][C:5]=1[CH2:23][CH2:24][CH2:25][CH2:26][CH2:27][CH2:28]Br)(=[O:3])[CH3:2].[I-].[Na+].[ClH:32].[C:33]1([C:39]2([C:45]3[CH:50]=[CH:49][CH:48]=[CH:47][CH:46]=3)[CH2:44][CH2:43][NH:42][CH2:41][CH2:40]2)[CH:38]=[CH:37][CH:36]=[CH:35][CH:34]=1>C(#N)C.C(OCC)C>[ClH:32].[C:1]([C:4]1[CH:9]([C:10]2[CH:15]=[CH:14][CH:13]=[C:12]([N+:16]([O-:18])=[O:17])[CH:11]=2)[C:8]([C:19](=[O:21])[CH3:20])=[C:7]([CH3:22])[NH:6][C:5]=1[CH2:23][CH2:24][CH2:25][CH2:26][CH2:27][CH2:28][N:42]1[CH2:43][CH2:44][C:39]([C:33]2[CH:38]=[CH:37][CH:36]=[CH:35][CH:34]=2)([C:45]2[CH:50]=[CH:49][CH:48]=[CH:47][CH:46]=2)[CH2:40][CH2:41]1)(=[O:3])[CH3:2]