反应详情

A solution of methyl N-morpholinoacetate (0.85 g, 5.3 mmol) in 1:1 5N NaOH/THF (10 ml) was stirred at 50° C. for 1 h then neutralized to pH 3 with 6N HCl and concentrated. The yellowish solid was diluted with 1:1 MeOH/CH2Cl2 (25 ml), filtered to remove inorganic salts, and concentrated. The dilution, filtration and concentration were repeated to give morpholin-4-yl-acetic acid (695 mg, 90%) as a yellow solid.

1. concentrationconcentrated
2. additionThe yellowish solid was diluted with 1:1 MeOH/CH2Cl2 (25 ml)
3. filtrationfiltered
4. customto remove inorganic salts
5. concentrationconcentrated
6. filtrationThe dilution, filtration and concentration