Eugenol → Coniferyl Alcohol
Reaction equation
[CH3:1][O:2][C:3]1[CH:4]=[C:5](/[CH:10]=[CH:11]/[CH:12]=[O:13])[CH:6]=[CH:7][C:8]=1[OH:9].C(O)(=O)C1C=CC(O)=C(OC)C=1.C1(OC)C(=CC=C(C=1)CC=C)O>>[CH2:12]([OH:13])/[CH:11]=[CH:10]/[C:5]1[CH:6]=[CH:7][C:8]([OH:9])=[C:3]([O:2][CH3:1])[CH:4]=1Participants
4
Procedure
The yield of coniferyl alcohol was 3226 ppm. This corresponds to 43.5% of theory. In addition, a further 1738 ppm (25% of theory) of ferulic acid were also obtained, as well as 12 ppm of coniferyl aldehyde and 8 ppm of vanillic acid. At the end of the process, 496 ppm (7.3%) of unreacted eugenol were still present.
Sources & evidence
- ORD record
- ord-ab857b1563ba45baa764ced3f395f90b
- Source dataset
- uspto-grants-1996_04
- Patent number
- US05510252
Reaction notes
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