Acetic Acid → 2-Fluoro-4-methyl-6-nitrophenol
Reaction equation
[N+:1]([O-:4])(O)=[O:2].C(O)(=O)C.[F:9][C:10]1[CH:15]=[C:14]([CH3:16])[CH:13]=[CH:12][C:11]=1[OH:17]>O>[F:9][C:10]1[CH:15]=[C:14]([CH3:16])[CH:13]=[C:12]([N+:1]([O-:4])=[O:2])[C:11]=1[OH:17]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
70% Nitric acid (d=1.42) (5.5 ml, 87.4 mmol) was dropwise added to an acetic acid (105 ml) solution of 2-fluoro-4-methyl-phenol (10.5 g, 83.2 mmol), taking 20 minutes, followed by stirring at room temperature for 30 minutes. Water was added to the reaction liquid, followed by extraction three times with diethyl ether, the organic layer was washed with saturated brine, dried over anhydrous magnesium sulfate. After filtration and concentration under reduced pressure, the resulting residue was subjected to column chromatography, and the eluate with n-hexane:ethyl acetate (10:1) was concentrated under reduced pressure to obtain the entitled compound (5.47 g, 31%) as a yellow solid.
Workup
- extractionfollowed by extraction three times with diethyl ether
- washthe organic layer was washed with saturated brine
- dry with materialdried over anhydrous magnesium sulfate
- filtrationAfter filtration and concentration under reduced pressure
- concentrationthe eluate with n-hexane:ethyl acetate (10:1) was concentrated under reduced pressure
Sources & evidence
- ORD record
- ord-e1ec134b539f42d393827d72b1772b35
- Source dataset
- uspto-grants-2010_06
- Patent number
- US07737166B2
Reaction notes
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