Formic Acid → Melamine formaldehyde
Reaction equation
[N:1]1[C:8]([NH2:9])=[N:7][C:5]([NH2:6])=[N:4][C:2]=1[NH2:3].C=O.[CH:12](O)=[O:13].[OH-].[Na+]>CO>[N:1]1[C:8]([NH2:9])=[N:7][C:5]([NH2:6])=[N:4][C:2]=1[NH2:3].[CH2:12]=[O:13]Participants
6
Reactant 4
Product 1
Reagents, catalysts & solvents 1
Procedure
126 g (1 mole) of melamine were methylolated in the presence of 270 g (9 moles) of formaldehyde at a pH of 8.5 and at from 40° to 70°C. The resulting adduct was brought to a pH of 4 with formic acid and etherified at 60° C. with 900 g of methanol in the course of 15 minutes. After neutralization with sodium hydroxide solution, the reactionsolution was freed from the unconverted formaldehyde and the excess methanol by evaporation (distillation).
Workup
- customthe excess methanol by evaporation (distillation)
Sources & evidence
- ORD record
- ord-f189a9bb7b894e53b91307586e348961
- Source dataset
- uspto-grants-1994_07
- Patent number
- US05330846
Reaction notes
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