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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1729311Generated: October 31, 2026

Catechol → HCID 13792091, compound

https://huagongshe.com/reaction/1729311

Reaction equation

Participants

RoleNameHCIDCharge
ReactantCatecholHCID 289—
ReactantChloroacetoneHCID 6571—
ReactantSodium HydroxideHCID 14798—
ReactantSodium BicarbonateHCID 516892—
SolventWaterHCID 962—
SolventIsopropanolHCID 3776—
ProductHCID 13792091HCID 1379209146.6%

Reaction Steps

11 g of catechol, 16.8 g of sodium hydrogencarbonate and 9.5 g of monochloroacetone were dissolved in a mixed solvent of 300 ml of water and 100 ml of isopropyl alcohol, and the solution was heated up to 50° to 60° C. and then stirred for 4 hours. Afterward, 50 ml of a 8% aqueous sodium hydroxide solution and 9.3 g of monochloroacetone were further added, followed by stirring at 50° C. for 5 hours. After standing for cooling, insolubles were removed from the solution by filtration, and the resultant filtrate was concentrated until the volume of the solution became about 300 ml, and then extracted with chloroform. The chloroform layer was washed with a dilute aqueous sodium hydroxide solution and then with water. The solvent was distilled off, and the residue was purified through a silica gel column chromatograph (chloroform/hexane=7/3 to chloroform alone in volume ratio), and then recrystallized from ether/hexane, thereby obtaining 7.73 g of crystals of 2-acetonyloxyphenol.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05332739
Source datasetuspto-grants-1994_07
ORD IDord-721ffc14fcc5488485b5e81646ffebbf
Source noteuspto-grants-1994_07