Water → Stearic Acid
Reaction equation
S([O-])([O:4][CH2:5][CH2:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][CH2:15][CH3:16])(=O)=O.[Na+].[OH2:19]>>[C:5]([OH:19])(=[O:4])[CH2:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][CH2:15][CH2:16][CH2:5][CH2:6][CH2:7][CH2:8][CH2:9][CH3:10]Participants
3
Reactant 2
Product 1
Procedure
Example 1 is illustrated by FIG. 1. The thermally-insulated vessel B1 contains an emulsion whose continuous phase consists of 10 metric tons of water containing 1% by weight of a surface-active agent consisting of sodium lauryl sulfate; the dispersed phase of the emulsion is formed of 10 metric tons of stearic acid whose melting point is 69° C. The volume of the emulsion is 21.76 m3 at 80° C. and 20.62 m3 at 60° C. in view of the difference of the volumic mass of stearic acid.
Sources & evidence
- ORD record
- ord-11927f42ed8d4bb6b111ac2a230f6571
- Source dataset
- uspto-grants-1980_12
- Patent number
- US04237964
Reaction notes
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