Sulfuryl chloride → HCID 12593653, compound
Reaction equation
S(Cl)(Cl)(=O)=O.[C:6]1([S:12][CH:13]2[C:17]([C:18]#[N:19])=[CH:16][S:15][CH2:14]2)[CH:11]=[CH:10][CH:9]=[CH:8][CH:7]=1>C(Cl)Cl>[C:6]1([S:12][C:13]2[C:17]([C:18]#[N:19])=[CH:16][S:15][CH:14]=2)[CH:7]=[CH:8][CH:9]=[CH:10][CH:11]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
3.6 Parts by volume of sulfuryl chloride in 25 parts by volume of methylene chloride are added, at 0° C., to a solution of 8.76 parts of 3-phenylthio-4-dihydrothiophene-nitrile in 100 parts by volume of methylene chloride. During the reaction, nitrogen is passed into the mixture. The end product is isolated from the reaction mixture by the method described in Example 5c. 7.8 parts (90% of theory) of 3-phenylthio-4-thiophene-nitrile of melting point 32°-34° C. are obtained.
Workup
- customDuring the reaction, nitrogen
- customThe end product is isolated from the reaction mixture by the method
Sources & evidence
- ORD record
- ord-f61263d7b3aa490299fa3f40fa013498
- Source dataset
- uspto-grants-1980_12
- Patent number
- US04239897
Reaction notes
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