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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1743580Generated: October 30, 2026

2-Fluoroethyl bromide → HCID 22235000, compound

https://huagongshe.com/reaction/1743580

Reaction equation

Participants

RoleNameHCIDCharge
Reactant2-Fluoroethyl bromideHCID 12982—
ReactantSodium hydrideHCID 24758—
ReactantHCID 11345355HCID 11345355—
SolventDimethylformamideHCID 6228—
ProductHCID 22235000HCID 2223500048.8%

Reaction Steps

Using 0.47 g of (4-bromobenzyl)malononitrile, 5 ml of N,N-di-methylformamide, 0.12 g of sodium hydride (60% in oil), and 0.25 g of 1-bromo-2-fluoroethane, and according to the process described in the Production Example 1, there was obtained 0.27 g of 2-(4-bromobenzyl)-2-(2-fluoroethyl)malononitrile (the present compound (51)).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07011838B2
Source datasetuspto-grants-2006_03
ORD IDord-49f061d4c11849fba6b39e960fb8a19f
Source noteuspto-grants-2006_03