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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1752041Generated: October 28, 2026

Iodoethane → 4-ethoxy-tetrahydro-4-(4-iodophenyl)-2H-pyran

https://huagongshe.com/reaction/1752041

Reaction equation

Participants

RoleNameHCIDCharge
ReactantIodoethaneHCID 6340—
Reactanttetrahydro-4-(4-iodophenyl)-2H-pyran-4-olHCID 57033480—
Product4-ethoxy-tetrahydro-4-(4-iodophenyl)-2H-pyranHCID 57762638—

Reaction Steps

In the same manner as in Reference Example 2, tetrahydro-4-(4-iodophenyl)-2H-pyran-4-ol (302 mg) and iodoethane (0.119 ml) were reacted to obtain 4-ethoxy-tetrahydro-4-(4-iodophenyl)-2H-pyran (269 mg).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS09162988B2
Source datasetuspto-grants-2015_10
ORD IDord-c896246bf88049f5814ce880760d81bc
Source noteuspto-grants-2015_10