HRID1756364

反应详情

EQUATION

反应方程式

HRID 1756364 的结构方程式

PROCEDURE

实验过程

Using a similar procedure to that described in Example 1, but starting from 2-ethylhexanoyl chloride and (A), there was obtained the title compound in 76% yield; partial NMR: 0.84(m,6H, 2×CH3), 1.24[m,6H, (CH2)3 ], 2.24(m,1H, CHCON), 10.78(d,1H, NH).