Phthalic Acid → Copper phthalate
Reaction equation
[C:1]([OH:12])(=[O:11])[C:2]1[C:3](=[CH:7][CH:8]=[CH:9][CH:10]=1)[C:4]([OH:6])=[O:5].[Cu:13]>O.[Cl-].C([N+](CC)(CC)CC)C.C(O)C>[C:1]([O-:12])(=[O:11])[C:2]1[C:3](=[CH:7][CH:8]=[CH:9][CH:10]=1)[C:4]([O-:6])=[O:5].[Cu+2:13]Participants
5
Reagents, catalysts & solvents 2
Procedure
To a reaction flask was charged 19.93 g (0.120 mole) of phthalic acid, 100 g of ethanol and 0.50 g of tetraethylammonium chloride hydrate. Copper foil was used as the anode and a graphite rod as the cathode. After passing 9,964 coulombs of electricity, 3.0 g (0.047 mole) of copper was consumed. The solvent was stripped off at reduced pressure to give a blue solid of copper phthalate containing 25.25% copper.
Workup
- customwas consumed
Sources & evidence
- ORD record
- ord-e07d2779699949e98692adca0a0617f6
- Source dataset
- uspto-grants-1995_08
- Patent number
- US05443698
Reaction notes
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