1-Chlorooctane → Octyl phenyl ether

HRID 1758359Notes

Reaction equation

HRID 1758359 reaction equation
Cl[CH2:2][CH2:3][CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][CH3:9].[CH:10]1[CH:15]=[CH:14][C:13]([O-:16])=[CH:12][CH:11]=1.[Na+]>>[O:16]([CH2:2][CH2:3][CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][CH3:9])[C:13]1[CH:14]=[CH:15][CH:10]=[CH:11][CH:12]=1

Participants

3

Reactant 2

HCID 81421-ChlorooctaneHCID 4445035Phenolate Sodium

Product 1

HCID 74558Octyl phenyl etherYield 96%

Conditions

Temperature
140 °C

Procedure

Into a 100 ml reactor equipped with a reflux condenser and a magnetic stirrer, 17 g 1-chlorooctane, 1.16 g anhydrous sodium phenate and 0.31 g of the product prepared according to Example 1, were introduced. The mixture was heated to 140° C. for 3 hours, 30 minutes. 1-Phenoxyoctane was obtained in a yield of 96%. The mixture was filtered after cooling and the precipitate washed with water and methanol.

Workup

  1. customInto a 100 ml reactor equipped with a reflux condenser and a magnetic stirrer
  2. additionwere introduced

Sources & evidence

ORD record
ord-328dca0237404e0bb1073b3a049b8462
Source dataset
uspto-grants-1983_02
Patent number
US04373070

Reaction notes

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