反应详情

In a suitable glass container is placed 9.9 gm. of octylphenoxypoly(ethyleneoxy) ethanol, dissolved in 50 ml. of water to which is added 0.1 gm. of potassium iodide. The mixture is then acid to a pH of below 3 and 0.02 gm. of iodate ion added with stirring. After standing for twenty-four hours, the solvent is evaporated under vacuum and the formed octylphenoxypoly-(ethyleneoxy)ethanol-iodine is obtained in substantially pure form, without iodide ions.

1. waitAfter standing for twenty-four hours
2. customthe solvent is evaporated under vacuum