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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1784210Generated: November 1, 2026

Lithium borohydride → HCID 67422856, compound

https://huagongshe.com/reaction/1784210

Reaction equation

Participants

RoleNameHCIDCharge
ReactantLithium borohydrideHCID 4148881—
ReactantHCID 67420362HCID 67420362—
SolventMethanolHCID 887—
SolventTetrahydrofuranHCID 8028—
SolventSodium HydroxideHCID 14798—
ProductHCID 67422856HCID 6742285699.6%

Reaction Steps

To a cold (0° C.) solution of 5-cyano-2-(3,3″-dichloro-3′,4′,5′,6′-tetrahydro-2′H-[2,2′;6′,2″]terpyridin-1′-ylmethyl)-benzoic acid methyl ester (391 mg, 0.813 mmol) in THF (4 mL) and MeOH (4 mL) was added LiBH4 (88 mg, 4.1 mmol), and the mixture was warmed to room temperature and stirred for 3.5 h. The mixture was diluted with 1.0 N NaOH (20 mL) and extracted with CH2Cl2 (4×10 mL). The combined organic extracts were dried (Na2SO4), filtered, and concentrated in vacuo to provide 4-(3,3″-Dichloro-3′,4′,5′,6′-tetrahydro-2′H-[2,2′;6′,2″]terpyridin-1′-ylmethyl)-3-hydroxymethyl-benzonitrile (367 mg) without any further purification. To a solution of the crude material (160 mg) in MeOH (4.5 mL) was added H2O (2.5 mL) and NaBO3.4H2O (108 mg, 0.707 mmol). The resultant mixture was heated to 50° C. for 5 h and stirred at room temperature overnight. The reaction mixture was concentrated and the residue was purified by flash chromatography on silica gel (CH2Cl2/MeOH/NH4OH, 90:5:5 then 85:10:5) to afford COMPOUND 52 (54 mg, 32% over 2 steps) as a white solid. 1H NMR (CDCl3) δ 1.63-1.79 (m, 3H), 1.93-2.06 (m, 1H), 2.11-2.30 (m, 2H), 2.33-2.47 (m, 2H), 3.63 (s, 2H), 4.59 (d, 2H, J=9.92 Hz), 4.41 (s, 2H), 4.99 (br s, 1H), 5.67 (br s, 1H), 6.15 (br s, 1H), 6.85-6.96 (m, 2H), 7.04 (d, 1H, J=7.8 Hz), 7.24 (d, 1H, J=1.8 Hz), 7.38 (d, 1H, J=1.5 Hz), 7.48 (dd, 2H, J=7.8, 1.5 Hz), 8.30 (dd, 2H, J=4.5, 1.2 Hz); 13C NMR (CDCl3) δ 24.98, 31.59, 57.28, 62.72, 66.56, 123.45, 126.39, 128.11, 129.90, 131.55, 131.70, 137.47, 140.08, 142.64, 147.77, 158.55, 169.17; ES-MS m/z 473 (M+1+H). Anal. Calcd. for C24H24N4Cl2O2.0.5H2O: C, 60.01; H, 5.25; N, 11.66. Found: C, 60.00; H, 5.15; N, 11.49.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07501518B2
Source datasetuspto-grants-2009_03
ORD IDord-65a609bf873e4f87ae8f56f5fee6f767
Source noteuspto-grants-2009_03