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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1785338Generated: October 31, 2026

Hydrochloric Acid → HCID 86056334, compound

https://huagongshe.com/reaction/1785338

Reaction equation

Participants

RoleNameHCIDCharge
ReactantHydrochloric AcidHCID 313—
ReactantMethyl iodideHCID 6328—
ReactantPotassium CarbonateHCID 11430—
ReactantHCID 59752448HCID 59752448—
SolventAcetoneHCID 180—
SolventEthyl AcetateHCID 8857—
ProductHCID 86056334HCID 8605633497.5%

Reaction Steps

2-(Dec-9-enyl)-tridec-12-enoic acid (63 mg, 0.18 mmol, Example 67) was added to a 100 mL three-neck round-bottom flask fitted with a reflux condenser (cooled with ice cold water) followed by 15 mL of reagent-grade acetone. The resulting solution was vigorously stirred and 0.062 g K2CO3 (0.45 mmol, 2.5 eq.) was added in one portion and the mixture was stirred for 5 minutes at room temperature. An excess of methyl iodide (˜2.0 mL) was then added and the mixture was refluxed under argon for 24 hours, after which TLC analysis (5:95 ethyl acetate:hexanes) indicated complete reaction. The mixture was acidified to pH 5 with 3N aqueous HCl and extracted with CH2Cl2. This solution was dried over MgSO4 and a small amount of Na2S2O3 (to destroy iodine). The solvent was then evaporated to afford methyl 2-(dec-9-enyl)-tridec-12-enoate (64 mg, quantitative yield) as a clear oil. 1H NMR (300 MHz, CDCl3): δ 5.80 (m, 2H), 4.93 (m, 4H), 3.65 (s, 1H), 2.35 (m, 1H), 2.03 (q, 4H), 1.58 (m, 2H) 1.42, 1.35, and 1.27 (m, 28H) ppm. 13C NMR (75 MHz, CDCl3): δ 177.04, 139.17, 139.15, 114.08, 114.06, 51.23, 45.68, 33.78 (2 C, unresolved), 32.48, 29.51, 29.50, 29.48 (2 C, unresolved), 29.42 (2 C, unresolved), 29.37 (2 C, unresolved), 29.09, 29.06, 28.90, 28.88, 27.44 (2 C, unresolved) ppm. Analysis calculated for C24H44O2: C, 79.06; H, 12.16. Found: C, 78.83; H, 12.16. HRMS-FAB: Theoretical: 365.3420; Found: 365.3399 [M]+. A copolymer of methyl 2-(dec-9-enyl)-tridec-12-enoate and 1,9-decadiene, prepared similarly to polymer 21, would have the following features: The end groups R2 and R3 would be H. For this polymer, e and f would be derived from methyl 2-(dec-9-enyl)-tridec-12-enoate and would equal 9 and 10, respectively; d would derive from 1,9-decadiene and would equal 8. The run length distribution would therefore be: rHH=(9+0)+8z; rHT=(9+10)+8z; and rTT=(10+10)+8z; therefore rtotal=(18+8z),(19+8z),(20+8z).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07504465B2
Source datasetuspto-grants-2009_03
ORD IDord-e0586bdcbf7f473a8af6a2419676ba4e
Source noteuspto-grants-2009_03