Potassium Hydroxide → HCID 68928806, compound

HRID 1788474Notes

Reaction equation

HRID 1788474 reaction equation
[C:1]1([C:7]2C=CC3C(=CC(C(O)=O)=CC=3)[N:8]=2)[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.C[O:21][C:22](=[O:32])C1C=CC(C=O)=C(N)C=1.[Br:33][C:34]1[CH:39]=[CH:38][CH:37]=[CH:36][C:35]=1[C:40](=O)[CH2:41][C:42]1[CH:47]=[CH:46][CH:45]=[CH:44][CH:43]=1.[OH-].[K+]>C(O)C>[Br:33][C:34]1[CH:39]=[CH:38][CH:37]=[CH:36][C:35]=1[C:40]1[C:7]([C:1]2[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=2)=[N:8][C:47]2[C:42]([CH:41]=1)=[CH:43][C:44]([C:22]([OH:32])=[O:21])=[CH:45][CH:46]=2

Participants

6

Reactant 4

HCID 14797Potassium HydroxideHCID 126898281-(2-Bromophenyl)-2-phenylethan-1-oneHCID 159468712-Phenylquinoline-7-carboxylic acidHCID 18412577Methyl 3-amino-4-formylbenzoate

Product 1

HCID 68928806HCID 68928806, compoundYield 40%

Reagents, catalysts & solvents 1

HCID 702EthanolSolvent2×

Procedure

Following the same reaction procedure and workup as for Compound 405f (235 mg, 1.31 mmol) of Compound 53 was reacted with the product of the previous reaction, Compound 424b (360 mg, 1.31 mmol), in ethanol (12 mL) using 10% w/v KOH in ethanol (1.1 mL) to produce the title compound (210 mg, 40% yield).

Sources & evidence

ORD record
ord-ac96ea8dd609482fadcaf9874f73ccec
Source dataset
uspto-grants-2009_03
Patent number
US07511145B2

Reaction notes

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