Potassium Hydroxide → HCID 5276048, compound

HRID 1788488Notes

Reaction equation

HRID 1788488 reaction equation
Br[C:2]1[CH:3]=[CH:4][C:5](O)=[C:6]([C:8]2[CH:17]=[CH:16][C:15]3[C:10](=[CH:11][CH:12]=[C:13]([C:18]4[N:22]([CH:23]5[CH2:28][CH2:27][CH2:26][CH2:25][CH2:24]5)[C:21]5[CH:29]=[CH:30][C:31]([C:33]([OH:35])=[O:34])=[CH:32][C:20]=5[N:19]=4)[CH:14]=3)[N:9]=2)[CH:7]=1.[O:37](C1C=CC(C(=O)C)=CC=1)[C:38]1[CH:43]=[CH:42][CH:41]=[CH:40][CH:39]=1.[OH-].[K+]>C(O)C>[CH:23]1([N:22]2[C:21]3[CH:29]=[CH:30][C:31]([C:33]([OH:35])=[O:34])=[CH:32][C:20]=3[N:19]=[C:18]2[C:13]2[CH:14]=[C:15]3[C:10](=[CH:11][CH:12]=2)[N:9]=[C:8]([C:6]2[CH:5]=[CH:4][C:3]([O:37][C:38]4[CH:43]=[CH:42][CH:41]=[CH:40][CH:39]=4)=[CH:2][CH:7]=2)[CH:17]=[CH:16]3)[CH2:24][CH2:25][CH2:26][CH2:27][CH2:28]1

Participants

5

Procedure

Following the procedure and workup for Compound 354, Compound 354e (100 mg, 0.256 mmol) was reacted with 1-(4-phenoxy-phenyl)-ethanone (0.256 mmol) in ethanol (2 mL) using 10% w/v KOH in Ethanol (506 μL, 0.64 mmol) to produce the title compound (42 mg, 31% yield).

Sources & evidence

ORD record
ord-74d401b8ec4242da885bcb02ec2dc6e1
Source dataset
uspto-grants-2009_03
Patent number
US07511145B2

Reaction notes

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