2-Fluoro-4-methyl-6-nitrophenol → 2-Amino-6-fluoro-4-methylphenol
Reaction equation
[F:1][C:2]1[CH:7]=[C:6]([CH3:8])[CH:5]=[C:4]([N+:9]([O-])=O)[C:3]=1[OH:12].[H][H]>C(O)C.[Pd]>[F:1][C:2]1[CH:7]=[C:6]([CH3:8])[CH:5]=[C:4]([NH2:9])[C:3]=1[OH:12]Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
A solution of 2-fluoro-4-methyl-6-nitrophenol (400 mg, 2.337 mmol) (D15) in ethanol (50 mL) was hydrogenated using a Pd/C cartridge in the H-cube™ hydrogenator at 1 mL/min and full hydrogen. Evaporation gave 2-fluoro-4-methyl-6-aminophenol (250 mg, 1.771 mmol, 76% yield) as a fawn solid.
Workup
- customEvaporation
Sources & evidence
- ORD record
- ord-567bc3c7879a4419b18a4d83be338342
- Source dataset
- uspto-grants-2013_01
- Patent number
- US08344000B2
Reaction notes
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