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HRID1804325

反应详情

EQUATION

反应方程式

HRID 1804325 的结构方程式

REACTANTS

反应物

2
结构：CI
HCID6328

Methyl iodide

CH3I

结构：O=C(c1ccc(N2C(=O)OC[C@H]2CO)nc1)N1CCN(c2ncc(C3CC3)cc2C2CC2)CC1
HCID58484584

未命名化合物

PRODUCTS

生成物

1
结构：COC[C@@H]1COC(=O)N1c1ccc(C(=O)N2CCN(c3ncc(C4CC4)cc3C3CC3)CC2)cn1
HCID58484834

未命名化合物

PROCEDURE

实验过程

By reaction and treatment in the same manner as in Example 73 and using (R)-3-{5-[4-(3,5-dicyclopropylpyridin-2-yl)piperazine-1-carbonyl]pyridin-2-yl}-4-hydroxymethyloxazolidin-2-one (310 mg) described in Example 252 and methyl iodide (50 μL), the title compound (85 mg) was obtained.

WORKUP

后处理

  1. customBy reaction and treatment in the same manner as in Example 73