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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1804683Generated: October 31, 2026

(2-Fluoro-3-methoxy-4-nitrophenyl)(morpholino)methanone → (4-Amino-2-fluoro-3-methoxyphenyl)(morpholino)methanone

https://huagongshe.com/reaction/1804683

Reaction equation

Participants

RoleNameHCIDCharge
Reactant(2-Fluoro-3-methoxy-4-nitrophenyl)(morpholino)methanoneHCID 70099135—
CatalystPalladiumHCID 23938—
SolventEthanolHCID 702—
Product(4-Amino-2-fluoro-3-methoxyphenyl)(morpholino)methanoneHCID 58539264—

Reaction Steps

A suspenion of (2-fluoro-3-methoxy-4-nitrophenyl)(morpholino)methanone (0.20 g) and palladium on carbon (0.1 g, 10 wt %) in ethanol was stirred under hydrogen for 18 hours. The reaction then filtered through celite and concentrated to give (4-amino-2-fluoro-3-methoxyphenyl)(morpholino)methanone.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08354420B2
Source datasetuspto-grants-2013_01
ORD IDord-ebc0b67471c84d5ba33200a119ebf431
Source noteuspto-grants-2013_01