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HRID1822265

反应详情

EQUATION

反应方程式

HRID 1822265 的结构方程式

REACTANTS

反应物

2
结构：Oc1ccccc1Oc1ccccc1
HCID75491

Phenol, 2-phenoxy-

C12H10O2

结构：COC(=O)CCc1ccc(Oc2cccc(Br)c2)cc1C
HCID57894192

未命名化合物

PRODUCTS

生成物

1
结构：Cc1cc(Oc2cccc(Oc3ccccc3Oc3ccccc3)c2)ccc1CCC(=O)O
HCID11154902

未命名化合物

PROCEDURE

实验过程

The title compound is prepared by reacting the compound of 3-[4-(3-bromo-phenoxy)-2-methyl-phenyl]-propionic acid methyl ester with 2-phenoxy-phenol as in Example 18 to afford 0.106 g (42%). 1H NMR (400 MHz, CDCl3); MS (ES+) m/z mass calculated for C28H24O5 440, found 441 (M+1).

WORKUP

后处理

  1. customto afford 0.106 g (42%)