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HRID1822305

反应详情

EQUATION

反应方程式

HRID 1822305 的结构方程式

REACTANTS

反应物

2
结构：Oc1ccccc1
HCID996

Phenol

C6H6O

结构：CCOC(=O)CCc1ccc(Oc2cc(F)cc(Oc3ccc(C(F)(F)F)cc3Br)c2)cc1C
HCID57894125

未命名化合物

PRODUCTS

生成物

1
结构：Cc1cc(Oc2cc(F)cc(Oc3ccc(C(F)(F)F)cc3Oc3ccccc3)c2)ccc1CCC(=O)O
HCID11752831

未命名化合物

PROCEDURE

实验过程

The title compound is prepare by reacting the compound of 3-{4-[3-(2-bromo-4-trifluoromethyl-phenoxy)-5-fluoro-phenoxy]-2-methyl-phenyl}-propionic acid ethyl ester with phenol as in Example 45 to afford 0.080 g (28%). 1H NMR (400 MHz, CDCl3); MS (ES+) m/z mass calculated for C29H22O5F4 526, found 527 (M+1, 100%).

WORKUP

后处理

  1. customto afford 0.080 g (28%)