3-Fluorophenol → HCID 11215128, compound

HRID 1822308Notes

Reaction equation

HRID 1822308 reaction equation
C([O:3][C:4](=[O:34])[CH2:5][CH2:6][C:7]1[CH:12]=[CH:11][C:10]([O:13][C:14]2[CH:19]=[C:18]([Cl:20])[CH:17]=[C:16]([O:21][C:22]3[CH:27]=[CH:26][C:25]([C:28]([F:31])([F:30])[F:29])=[CH:24][C:23]=3Br)[CH:15]=2)=[CH:9][C:8]=1[CH3:33])C.[F:35][C:36]1[CH:37]=[C:38]([OH:42])[CH:39]=[CH:40][CH:41]=1>>[Cl:20][C:18]1[CH:19]=[C:14]([CH:15]=[C:16]([O:21][C:22]2[CH:27]=[CH:26][C:25]([C:28]([F:29])([F:31])[F:30])=[CH:24][C:23]=2[O:42][C:38]2[CH:39]=[CH:40][CH:41]=[C:36]([F:35])[CH:37]=2)[CH:17]=1)[O:13][C:10]1[CH:11]=[CH:12][C:7]([CH2:6][CH2:5][C:4]([OH:3])=[O:34])=[C:8]([CH3:33])[CH:9]=1

Participants

3

Reactant 2

HCID 97433-FluorophenolHCID 69079112HCID 69079112, compound

Product 1

HCID 11215128HCID 11215128, compound

Procedure

The title compound is prepare by reacting the compound of 3-{4-[3-(2-Bromo-4-trifluoromethyl-phenoxy)-5-chloro-phenoxy]-2-methyl-phenyl}-propionic acid ethyl ester with 3-fluorophenol as in Example 45 to afford 0.025 g (23%). 1H NMR (400 MHz, CDCl3); MS (ES+) m/z mass calculated for C29H21O5F4Cl 560, found 578 and 580 (M+NH4, 100%).

Workup

  1. customto afford 0.025 g (23%)

Sources & evidence

ORD record
ord-963ca3a8a3c644c3abe531630f4b64a9
Source dataset
uspto-grants-2009_10
Patent number
US07608639B2

Reaction notes

Loading…