HRID1822454

反应详情

EQUATION

反应方程式

REACTANTS

反应物

反应SMILES：CC(C)(C)C[C@H](NC(=O)OC(C)(C)C)C(=O)O

HCID2755926

未命名化合物

PRODUCTS

产物

反应SMILES：C=C[C@@H]1C[C@]1(NC(=O)[C@@H]1C[C@@H](Oc2cc(-c3ccccc3)nc3cc(OC)ccc23)CN1C(=O)N[C@@H](CC(C)(C)C)C(=O)N[C@H]1c2ccccc2C[C@H]1O)C(=O)O

HCID57892901

未命名化合物

收率 30%

PROCEDURE

实验过程

(2S)-tert-butoxycarbonylamino-4,4-dimethylpentanoic acid was attached to the resin as described for the preparation of compound 16 followed by reaction with (1S,2R)-1-amino-2-indanol as described for the preparation of 17 and removal of the Boc group as described for 18. The afforded compound was then reacted with the chlorocarbamate achieved from 12 as described for the preparation of 13 which, after purification by HPLC, gave the title compound (14.2 mg, 30% yield), Purity by HPLC >95% M+H+776.3.

WORKUP

后处理

customafter purification by HPLC

来源与证据

来源类型: Open Reaction Database
ORD记录: ord-c31d6631214143efbb339cd36e74edad
来源数据集: uspto-grants-2009_10
DOI: 10.6084/m9.figshare.5104873.v1
专利号: US07608590B2
来源说明: uspto-grants-2009_10

反应SMILES

C(O[C:6]([NH:8][C@@H:9]([CH2:13][C:14]([CH3:17])([CH3:16])[CH3:15])[C:10]([OH:12])=O)=[O:7])(C)(C)C.C(OC(NC(C(C)(C)C)C(O)=O)=O)(C)(C)C.[NH2:34][C@H:35]1[C:43]2[C:38](=[CH:39][CH:40]=[CH:41][CH:42]=2)[CH2:37][C@H:36]1[OH:44].C(OC(=O)NC(C(=O)NC1C2C(=CC=CC=2)CC1O)C(C)(C)C)(C)(C)C.ClNC(=O)[O-].C([O:78][C:79]([C:81]1([NH:86][C:87]([CH:89]2[CH2:93][CH:92]([O:94][C:95]3[C:104]4[C:99](=[CH:100][C:101]([O:105][CH3:106])=[CH:102][CH:103]=4)[N:98]=[C:97]([C:107]4[CH:112]=[CH:111][CH:110]=[CH:109][CH:108]=4)[CH:96]=3)[CH2:91][N:90]2C(=O)NC(C(=O)NC2C3C(=CC=CC=3)CC2O)C(C)(C)C)=[O:88])[CH2:83][CH:82]1[CH:84]=[CH2:85])=[O:80])C>>[OH:44][C@@H:36]1[CH2:37][C:38]2[C:43](=[CH:42][CH:41]=[CH:40][CH:39]=2)[C@@H:35]1[NH:34][C:10]([C@@H:9]([NH:8][C:6]([N:90]1[CH2:91][C@H:92]([O:94][C:95]2[C:104]3[C:99](=[CH:100][C:101]([O:105][CH3:106])=[CH:102][CH:103]=3)[N:98]=[C:97]([C:107]3[CH:112]=[CH:111][CH:110]=[CH:109][CH:108]=3)[CH:96]=2)[CH2:93][C@H:89]1[C:87]([NH:86][C@:81]1([C:79]([OH:80])=[O:78])[CH2:83][C@H:82]1[CH:84]=[CH2:85])=[O:88])=[O:7])[CH2:13][C:14]([CH3:15])([CH3:16])[CH3:17])=[O:12]