Formaldehyde → Phosphoric Acid
Reaction equation
[CH2:1]=[O:2].[OH-:3].[Na+].[P:5]([OH:9])([OH:8])([OH:7])=[O:6].[NH2:10][C:11]([NH2:13])=[NH:12]>CO>[C:1](=[O:6])([OH:3])[OH:2].[NH2:12][C:11]([NH2:13])=[NH:10].[P:5](=[O:6])([OH:9])([OH:8])[OH:7]Participants
6
Reactant 3
Product 2
Reagents, catalysts & solvents 1
Procedure
189 grams of paraformaldehyde (6 moles) were dissolved in the heat in 298 grams of methanol with 1 gram of sodium hydroxide. Then there were added 2 moles of a hot, concentrated guanidine dihydrogen phosphate solution, which was previously produced from 180 grams of guanidine carbonate (1 mole) and 231 grams of 85% phosphoric acid (2 moles). After about one hour of boiling at reflux there was formed a clear solution to which there were added a further 2 moles of the previously described concentrated guanidine dihydrogen phosphate solution as well as 137 grams of methanol. The mixture was boiled at reflux for a further three hours, cooled and drawn off. It contained 60% solids, 31.5% methanol and 8.5% water.
Sources & evidence
- ORD record
- ord-a28a17cc3e7a42649a1a271dc1b4525c
- Source dataset
- uspto-grants-1980_08
- Patent number
- US04219456
Reaction notes
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