Formaldehyde → Phosphoric Acid
Reaction equation
[CH2:1]=[O:2].[OH-:3].[Na+].[P:5]([OH:9])([OH:8])([OH:7])=[O:6].[NH2:10][C:11]([NH2:13])=[NH:12]>CO>[C:1](=[O:6])([OH:3])[OH:2].[NH2:12][C:11]([NH2:13])=[NH:10].[P:5](=[O:6])([OH:9])([OH:8])[OH:7]Participants
6
Reactant 3
Product 2
Reagents, catalysts & solvents 1
Procedure
189 grams of paraformaldehyde (6 moles) were dissolved in the heat in 450 grams of methanol under the addition of 1 gram of sodium hydroxide. After addition of 390 grams of a hot guanidine phosphate solution, which had been previously produced from 180 grams of guanidine carbonate (1 mole) and 254 grams of 85% phosphoric acid (2.2 moles), the mixture was boiled at reflux for about one hour until a clear solution was obtained. Then there were added a further 250 grams of methanol as well as a further 434 grams of the above mentioned guanidine phosphate solution after which the mixture was heated at reflux for a further 41/2 hours. The solution formed contained 51.1% solids, 42.2% methanol and 6.7% water.
Sources & evidence
- ORD record
- ord-09d79b33ded849cca604fb40b6a9ca20
- Source dataset
- uspto-grants-1980_08
- Patent number
- US04219456
Reaction notes
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