Formaldehyde → Phosphoric Acid
Reaction equation
[CH2:1]=[O:2].[OH-:3].[Na+].[P:5]([OH:9])([OH:8])([OH:7])=[O:6].[NH2:10][C:11]([NH2:13])=[NH:12]>CO>[C:1](=[O:6])([OH:3])[OH:2].[NH2:12][C:11]([NH2:13])=[NH:10].[P:5](=[O:6])([OH:9])([OH:8])[OH:7]Participants
6
Reactant 3
Product 2
Reagents, catalysts & solvents 1
Procedure
189 grams of 95% paraformaldehyde (6 moles) were dissolved in the heat in 1000 grams of methanol with addition of 1 gram of sodium hydroxide and the mixture heated to reflux. Then in an interval of 1 hour there were added in 3 equal portions 1098 grams of a hot guanidine dihydrogen phosphate solution, which previously was produced from 540 grams of guanidine carbonate (3 moles) and 692 grams of 85% phosphoric acid (6 moles). After the end of the last addition, the mixture was heated for a further 3 hours at reflux, then cooled and drawn off. The solution contained 49.0% solids, 43.7% methanol and 7.3% water.
Workup
- temperaturethe mixture heated to reflux
Sources & evidence
- ORD record
- ord-8c790ab6834b4d718dc1c3120546737b
- Source dataset
- uspto-grants-1980_08
- Patent number
- US04219456
Reaction notes
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