Formaldehyde → Phosphoric Acid
Reaction equation
[CH2:1]=[O:2].[OH-:3].[Na+].[P:5]([OH:9])([OH:8])([OH:7])=[O:6].[NH2:10][C:11]([NH2:13])=[NH:12]>C(O)C>[C:1](=[O:6])([OH:3])[OH:2].[NH2:12][C:11]([NH2:13])=[NH:10].[P:5](=[O:6])([OH:9])([OH:8])[OH:7]Participants
6
Reactant 3
Product 2
Reagents, catalysts & solvents 1
Procedure
189 grams of 95% paraformaldehyde were dissolved in the heat in 700 grams of ethanol together with 1 gram of sodium hydroxide and heated to reflux. Then in an interval of 3 hours there were added in two equal parts 732 grams of a hot guanidine dihydrogen phosphate solution which had been previously produced from 360 grams of guanidine carbonate (2 moles) and 461 grams of 85% phosphoric acid (4 moles). After the second addition the mixture was heated at reflux for a further 5 hours, then allowed to cool and drawn off. The product corresponds in the molar ratios to those of Examples 5, is dilutable in ethanol and has the composition, solids 49.7%, ethanol 43.2% and water 7.1%.
Workup
- temperatureheated to reflux
Sources & evidence
- ORD record
- ord-cd1cbfb4dbca406eba2d50a5f2880126
- Source dataset
- uspto-grants-1980_08
- Patent number
- US04219456
Reaction notes
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