Z-Pal-N(Me)Bzl → H-Pal-N(Me)Bzl
Reaction equation
[NH:1](C(OCC1C=CC=CC=1)=O)[C@H:2]([C:10]([N:12]([CH2:14][C:15]1[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=1)[CH3:13])=[O:11])[CH2:3][C:4]1[CH:9]=[N:8][CH:7]=[CH:6][CH:5]=1>CO.[Pd].[C]>[NH2:1][C@H:2]([C:10]([N:12]([CH2:14][C:15]1[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=1)[CH3:13])=[O:11])[CH2:3][C:4]1[CH:9]=[N:8][CH:7]=[CH:6][CH:5]=1Participants
4
Reactant 1
Product 1
Reagents, catalysts & solvents 2
Procedure
2.68 g of Z-Pal-N(Me)Bzl (6.85 mMol) are dissolved in 30 ml of MeOH and after adding 0.3 g of Pd-carbon hydrogenated for 5 hours at ambient temperature and 5 bar. Then, the mixture is filtered, the filtrate is concentrated on the rotary evaporator, the residue is dissolved in ether, filtered and the filtrate is again concentrated. H-Pal-N(Me)Bzl is obtained as a light green oil.
Workup
- filtrationThen, the mixture is filtered
- concentrationthe filtrate is concentrated on the rotary evaporator
- dissolutionthe residue is dissolved in ether
- filtrationfiltered
- concentrationthe filtrate is again concentrated
Sources & evidence
- ORD record
- ord-d9be86e9082c42428fc8fa6c5f2e9c12
- Source dataset
- uspto-grants-2000_11
- Patent number
- US06147212
Reaction notes
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