Z-Pal-N(Me)Bzl → H-Pal-N(Me)Bzl

HRID 1857681Notes

Reaction equation

HRID 1857681 reaction equation
[NH:1](C(OCC1C=CC=CC=1)=O)[C@H:2]([C:10]([N:12]([CH2:14][C:15]1[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=1)[CH3:13])=[O:11])[CH2:3][C:4]1[CH:9]=[N:8][CH:7]=[CH:6][CH:5]=1>CO.[Pd].[C]>[NH2:1][C@H:2]([C:10]([N:12]([CH2:14][C:15]1[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=1)[CH3:13])=[O:11])[CH2:3][C:4]1[CH:9]=[N:8][CH:7]=[CH:6][CH:5]=1

Participants

4

Procedure

2.68 g of Z-Pal-N(Me)Bzl (6.85 mMol) are dissolved in 30 ml of MeOH and after adding 0.3 g of Pd-carbon hydrogenated for 5 hours at ambient temperature and 5 bar. Then, the mixture is filtered, the filtrate is concentrated on the rotary evaporator, the residue is dissolved in ether, filtered and the filtrate is again concentrated. H-Pal-N(Me)Bzl is obtained as a light green oil.

Workup

  1. filtrationThen, the mixture is filtered
  2. concentrationthe filtrate is concentrated on the rotary evaporator
  3. dissolutionthe residue is dissolved in ether
  4. filtrationfiltered
  5. concentrationthe filtrate is again concentrated

Sources & evidence

ORD record
ord-d9be86e9082c42428fc8fa6c5f2e9c12
Source dataset
uspto-grants-2000_11
Patent number
US06147212

Reaction notes

Loading…