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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1859827Generated: November 2, 2026

2-(1H-imidazol-1-yl)-1-phenylethanol → 6-[2-(1H-1-Imidazolyl)-1-phenylethoxy]-1,2,3,4-tetrahydro-1-naphthalenone

https://huagongshe.com/reaction/1859827

Reaction equation

Participants

RoleNameHCIDCharge
Reactant2-(1H-imidazol-1-yl)-1-phenylethanolHCID 32239—
Reactant6-(2-Imidazole-1-yl-ethoxy)-3,4-dihydro-2H-naphthalen-1-oneHCID 15486912—
Product6-[2-(1H-1-Imidazolyl)-1-phenylethoxy]-1,2,3,4-tetrahydro-1-naphthalenoneHCID 10268489288.1%

Reaction Steps

Following the procedure of Example 78, Step 3, but using 2.63 g (4.0 mmol) of 2-(1H-1-imidazolyl)-1-phenyl-1-ethanol and 2.0 g (12.3 mmol) of 6-[2-(1-H-1-imidazolyl)ethoxy]1,2,3,4-tetrahydro -1-naphthalenone, there was obtained 3.83 g (93.6% yield) of the product as a glass. The structure was confirmed by NMR and mass spectroscopy. MS m/z 333 (M+H+).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06528535B2
Source datasetuspto-grants-2003_03
ORD IDord-1f332f0caea44d39a4d9625dbeb87690
Source noteuspto-grants-2003_03