Sodium Hydroxide → HCID 10412670, compound

HRID 1859872Notes

Reaction equation

HRID 1859872 reaction equation
[CH2:1]([CH:5]([CH2:11][C:12]1[CH:17]=[CH:16][C:15]([O:18][CH2:19][CH2:20][NH:21][C:22]([C:24]2[CH:29]=[CH:28][C:27]([C:30]3[CH:35]=[CH:34][CH:33]=[CH:32][C:31]=3[O:36][CH3:37])=[CH:26][CH:25]=2)=[O:23])=[CH:14][CH:13]=1)[C:6]([O:8]CC)=[O:7])[CH2:2][CH2:3][CH3:4].[OH-].[Na+]>>[CH2:1]([CH:5]([CH2:11][C:12]1[CH:13]=[CH:14][C:15]([O:18][CH2:19][CH2:20][NH:21][C:22]([C:24]2[CH:25]=[CH:26][C:27]([C:30]3[CH:35]=[CH:34][CH:33]=[CH:32][C:31]=3[O:36][CH3:37])=[CH:28][CH:29]=2)=[O:23])=[CH:16][CH:17]=1)[C:6]([OH:8])=[O:7])[CH2:2][CH2:3][CH3:4]

Participants

3

Reactant 2

HCID 14798Sodium HydroxideHCID 18625856Ethyl 2-butyl-3-[4-[2-(2'-methoxybiphenyl-4-carbonylamino)ethoxy]phenyl]propionate

Product 1

HCID 10412670HCID 10412670, compoundYield 88.2%

Procedure

In a similar manner to that described in Example 2, ethyl 2-butyl-3-[4-[2-(2′-methoxybiphenyl-4-carbonylamino)ethoxy]phenyl]propionate (750 mg), which is the product of Example 42, was reacted with aqueous sodium hydroxide solution (1N, 5.00 ml) and the reaction mixture was treated to give the title compound (625 mg) as a pale orange powder.

Workup

  1. additionthe reaction mixture was treated

Sources & evidence

ORD record
ord-97c3b30546c544389ac699f3cada0a0c
Source dataset
uspto-grants-2003_03
Patent number
US06528525B1

Reaction notes

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