Sodium Hydroxide → HCID 9984270, compound

HRID 1859892Notes

Reaction equation

HRID 1859892 reaction equation
[C:1]1([C:36]2[CH:41]=[CH:40][CH:39]=[CH:38][CH:37]=2)[CH:6]=[CH:5][C:4]([C:7]([NH:9][CH2:10][CH2:11][O:12][C:13]2[CH:18]=[CH:17][C:16]([CH2:19][CH:20]([O:26][C:27]3[CH:32]=[CH:31][C:30]([CH:33]([CH3:35])[CH3:34])=[CH:29][CH:28]=3)[C:21]([O:23]CC)=[O:22])=[CH:15][CH:14]=2)=[O:8])=[CH:3][CH:2]=1.[OH-].[Na+]>>[C:1]1([C:36]2[CH:41]=[CH:40][CH:39]=[CH:38][CH:37]=2)[CH:2]=[CH:3][C:4]([C:7]([NH:9][CH2:10][CH2:11][O:12][C:13]2[CH:18]=[CH:17][C:16]([CH2:19][CH:20]([O:26][C:27]3[CH:28]=[CH:29][C:30]([CH:33]([CH3:35])[CH3:34])=[CH:31][CH:32]=3)[C:21]([OH:23])=[O:22])=[CH:15][CH:14]=2)=[O:8])=[CH:5][CH:6]=1

Participants

3

Reactant 2

HCID 14798Sodium HydroxideHCID 18625825HCID 18625825, compound2×

Product 1

HCID 9984270HCID 9984270, compoundYield 85.3%

Procedure

In a similar manner to that described in Example 2, ethyl 3-[4-[2-(biphenyl-4-carbonylamino)ethoxy]phenyl]-2-(4-isopropylphenoxy)propionate (630 mg), which is the product of Example 86, was reacted with aqueous sodium hydroxide solution (1N, 2.00 ml) and the reaction mixture was treated to give the title compound (510 mg) as a white powder.

Workup

  1. additionthe reaction mixture was treated

Sources & evidence

ORD record
ord-416769575be24d3a8832843c6e9c7e8c
Source dataset
uspto-grants-2003_03
Patent number
US06528525B1

Reaction notes

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