Sodium Hydroxide → HCID 9984819, compound

HRID 1859899Notes

Reaction equation

[F:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[CH:13]=[CH:12][C:11]([C:14]([NH:16][CH2:17][CH2:18][O:19][C:20]3[CH:25]=[CH:24][C:23]([CH2:26][CH:27]([O:33][C:34]4[CH:39]=[CH:38][C:37]([CH:40]([CH3:42])[CH3:41])=[CH:36][CH:35]=4)[C:28]([O:30]CC)=[O:29])=[CH:22][CH:21]=3)=[O:15])=[CH:10][N:9]=2)=[CH:4][CH:3]=1.[OH-].[Na+]>>[F:1][C:2]1[CH:3]=[CH:4][C:5]([C:8]2[CH:13]=[CH:12][C:11]([C:14]([NH:16][CH2:17][CH2:18][O:19][C:20]3[CH:25]=[CH:24][C:23]([CH2:26][CH:27]([O:33][C:34]4[CH:35]=[CH:36][C:37]([CH:40]([CH3:42])[CH3:41])=[CH:38][CH:39]=4)[C:28]([OH:30])=[O:29])=[CH:22][CH:21]=3)=[O:15])=[CH:10][N:9]=2)=[CH:6][CH:7]=1

Participants

Reactant 2

HCID 14798Sodium Hydroxide

HCID 18625823HCID 18625823, compound

Product 1

HCID 9984819HCID 9984819, compoundYield 96.4%

Procedure

In a similar manner to that described in Example 2, ethyl 3-[4-[2-[2-(4-fluorophenyl)pyridine-5-carbonylamino]ethoxy]-phenyl]-2-(4-isopropylphenoxy)propionate (540 mg), which is the product of Example 100, was reacted with aqueous sodium hydroxide solution (1N, 3.00 ml) and the reaction mixture was treated to give the title compound (495 mg) as a white powder.

Workup

additionthe reaction mixture was treated

Sources & evidence

ORD record: ord-45035e39c1fc478ebe39d75b56be6178
Source dataset: uspto-grants-2003_03
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US06528525B1

Reaction notes

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