HRID1860345

反应详情

EQUATION

反应方程式

REACTANTS

反应物

结构：O=C(O)c1ccc(OCc2ccc(F)cc2)c(OCc2ccc(F)cc2)c1

HCID18627055

3,4-Bis[(4-fluorophenyl)methoxy]benzoic acid

C21H16F2O4

结构：COc1ccc(NC(=O)[C@H](CCC(=O)NC(c2ccccc2)(c2ccccc2)c2ccccc2)NC(=O)OCC2c3ccccc3-c3ccccc32)cc1O

HCID22976129

未命名化合物

PRODUCTS

生成物

结构：COc1ccc(NC(=O)[C@H](CCC(=O)NC(c2ccccc2)(c2ccccc2)c2ccccc2)NC(=O)c2ccc(OCc3ccc(F)cc3)c(OCc3ccc(F)cc3)c2)cc1O

HCID504874

未命名化合物

PROCEDURE

实验过程

The title compound was prepared from N-[Nα-(9-fluorenylmethoxycarbonyl)-Nδ-trityl-L-glutaminyl]-3-hydroxy-4-methoxyaniline (642 mg, 0.9 mmol, example 109, step A) as described for example 109 (step B) using 3,4-di-(4-fluorobenzyloxy)benzoic acid (485 mg, 1.3 mmol) instead of N-(4-fluorobenzyl)indole-2-carboxylic acid. The crude material was purified by flash chromatography using successively 5%, 10% and 30% EtOAc/CH2Cl2 as the eluent. The title compound was obtained as white crystals (260 mg, 34%).

WORKUP

后处理

customThe crude material was purified by flash chromatography

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-aa23c12a7218480cb43f0872aa582902
来源数据集: uspto-grants-2003_03
DOI: 10.6084/m9.figshare.5104873.v1
专利: US06528655B1
来源说明: uspto-grants-2003_03

反应 SMILES

C1C2C(C[O:15][C:16]([NH:18][C@H:19]([C:44]([NH:46][C:47]3[CH:52]=[CH:51][C:50]([O:53][CH3:54])=[C:49]([OH:55])[CH:48]=3)=[O:45])[CH2:20][CH2:21][C:22](=[O:43])[NH:23][C:24]([C:37]3[CH:42]=[CH:41][CH:40]=[CH:39][CH:38]=3)([C:31]3[CH:36]=[CH:35][CH:34]=[CH:33][CH:32]=3)[C:25]3[CH:30]=[CH:29][CH:28]=[CH:27][CH:26]=3)=O)C3C(=CC=CC=3)C=2C=CC=1.[F:56][C:57]1[CH:82]=[CH:81][C:60]([CH2:61][O:62][C:63]2[CH:64]=[C:65]([CH:69]=[CH:70][C:71]=2[O:72][CH2:73][C:74]2[CH:79]=[CH:78][C:77]([F:80])=[CH:76][CH:75]=2)C(O)=O)=[CH:59][CH:58]=1>>[F:56][C:57]1[CH:82]=[CH:81][C:60]([CH2:61][O:62][C:63]2[CH:64]=[C:65]([CH:69]=[CH:70][C:71]=2[O:72][CH2:73][C:74]2[CH:79]=[CH:78][C:77]([F:80])=[CH:76][CH:75]=2)[C:16]([NH:18][C@H:19]([C:44]([NH:46][C:47]2[CH:52]=[CH:51][C:50]([O:53][CH3:54])=[C:49]([OH:55])[CH:48]=2)=[O:45])[CH2:20][CH2:21][C:22](=[O:43])[NH:23][C:24]([C:37]2[CH:38]=[CH:39][CH:40]=[CH:41][CH:42]=2)([C:25]2[CH:30]=[CH:29][CH:28]=[CH:27][CH:26]=2)[C:31]2[CH:32]=[CH:33][CH:34]=[CH:35][CH:36]=2)=[O:15])=[CH:59][CH:58]=1