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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1860698Generated: October 31, 2026

3-Bromoanisole → HCID 22397834, compound

https://huagongshe.com/reaction/1860698

Reaction equation

Participants

RoleNameHCIDCharge
Reactant3-BromoanisoleHCID 16971—
Reactant1-Benzyl-4-piperidoneHCID 19220—
ReactantButyllithiumHCID 178418339—
SolventTetrahydrofuranHCID 8028—
ProductHCID 22397834HCID 22397834—

Reaction Steps

3-Bromoanisole (50.0 g, 0.264 mol) was dissolved in 150 mL of THF and then chilled to −78° C. n-Butyllithium (1.6M, 175 mL, 0.276 mol) was then added while maintaining the reaction temperature at −70° C. or below. After complete addition, the reaction mixture was stirred for an additional 60 min. 1-Benzyl-4-piperidone in 150 mL of THF was then added at such a rate as to maintain the reaction temperature at −70° C. or below. The reaction was stirred at −70° C. for an additional 15 min, then the dry ice-acetone bath was removed, and the reaction was allowed to come to room temperature. Brine (400 mL) was added, and the organic layer was separated and washed with an additional 300 mL of brine. The organic layer was separated, dried (K2CO3), and concentrated in vacuo. 6N HCl (250 mL) was added to the oily residue which was then washed with EtOAc. The aqueous layer was separated, basified with 50% NaOH, and extracted with EtOAc. The EtOAc layer was separated, dried (K2CO3), and concentrated in vacuo to give 75.7 g of 4-(3-methoxyphenyl)-1-benzyl-4-piperidinol as an orange oil. A sample was chromatographed on silica gel using hexane/EtOAc (7:3) mixtures as the eluent to afford a yellow oil which was dissolved in ether and treated with ethereal hydrochloric acid to give 4-(3-methoxyphenyl)-1-benzyl-4-piperidinol hydrochloride as a white solid (mp 195-197° C.). 1H NMR (CDCl3) (free base) δ (ppm) 1.64-1.75 (m, 2H), 2.09-2.21 (m, 2H), 2.41-2.51 (m, 2H), 2.71-2.80 (m, 2H), 3.51 (s, 2H), 3.80 (s, 3H), 6.77-6.81 (m, 1H), 7.06-7.09 (m, 2H), 7.23-7.35 (m, 6H). Anal. Calcd for C19H23NO2 HCl.½H2O: C, 66.56; H, 7.06; N, 4.09. Found: C, 66.41; H, 7.31; N, 4.33.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06531481B2
Source datasetuspto-grants-2003_03
ORD IDord-cb0e0700957446fab727f310f2caacba
Source noteuspto-grants-2003_03