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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1863300Generated: October 27, 2026

Potassium Iodide → Methyl (m-[m-phenoxyphenoxy]phenoxy)-alpha-[p-(p-chlorophenoxy)phenyl]acetate

https://huagongshe.com/reaction/1863300

Reaction equation

Participants

RoleNameHCIDCharge
ReactantPotassium IodideHCID 4875—
ReactantPhenol, 3-(3-phenoxyphenoxy)-HCID 84251—
ReactantSodium MethoxideHCID 10942334—
ReactantMethyl alpha-Bromo-alpha-[p-(p-chlorophenoxy)phenyl]acetateHCID 20392594—
SolventBenzeneHCID 241—
SolventMethanolHCID 887—
SolventWaterHCID 962—
ProductMethyl (m-[m-phenoxyphenoxy]phenoxy)-alpha-[p-(p-chlorophenoxy)phenyl]acetateHCID 86736645—

Reaction Steps

To a solution of 6.96 g of m-(m-phenoxyphenoxy)phenol, 1.19 g of sodium methoxide and 50 mg of potassium iodide in 40 ml of methanol is added 7.11 g of methyl α-bromo-α-[p-(p-chlorophenoxy)phenyl]acetate in 10 ml of benzene. The mixture is refluxed for 20 hours, poured into ice and water and extracted with chloroform. The chloroform extracts are washed with 10% potassium carbonate and with water. The extract is dried over magnesium sulfate and concentrated under vacuum to give an oil. Filtration once through silica gel (chloroform solvent) and again through silica gel with benzene as solvent gives the product as an oil.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04168385
Source datasetuspto-grants-1979_09
ORD IDord-bda675eb7dbd4415a813c129aea4875b
Source noteuspto-grants-1979_09