HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1866498Generated: October 31, 2026
Hydrochloric Acid → (3-{(2R)-2-[(2R)-2-{[tert-butyl(dimethyl)silyl]oxy}-2-(4-hydroxy-3-hydroxymethyl-phenyl)-ethylamino]-propyl}-phenyl)-acetic acid
https://huagongshe.com/reaction/1866498
Participants
| Role | Name | HCID | Charge |
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| Reactant | Hydrochloric Acid | HCID 313 | — |
| Reactant | Lithium Hydroxide | HCID 3939 | — |
| Reactant | methyl (3-{(2R)-2-[(2R)-2-{[tert-butyl(dimethyl)silyl]oxy}-2-(4-hydroxy-3-hydroxymethyl-phenyl)-ethylamino]-propyl}-phenyl)-acetate | HCID 58959781 | — |
| Solvent | Tetrahydrofuran | HCID 8028 | — |
| Product | (3-{(2R)-2-[(2R)-2-{[tert-butyl(dimethyl)silyl]oxy}-2-(4-hydroxy-3-hydroxymethyl-phenyl)-ethylamino]-propyl}-phenyl)-acetic acid | HCID 58959819 | 87% |
Reaction Steps
A solution of methyl(3-{(2R)-2-[(2R)-2-{[tert-butyl(dimethyl)silyl]oxy}-2-(4-hydroxy-3-hydroxymethyl-phenyl)-ethylamino]-propyl}-phenyl)-acetate (Preparation 21) (7.04 g, 14.43 mmol) in tetrahydrofuran (40 ml) was treated with lithium hydroxide (28.9 ml of a 1M aqueous solution, 28.9 mmol) and the reaction left to stir at room temperature for 16 hours. Hydrochloric acid (28.9 ml of a 1M aqueous solution, 28.9 mmol) was added and then the tetrahydrofuran was removed in vacuo. The remaining aqueous layer was decanted and the residue washed with further water (10 ml). The residue was redisolved in methanol (30 ml) and the solvent removed in vacuo to give the title compound as a colorless foam (5.95 g) which was used without further purification. 1H NMR (400 MHz, CD3OD): δ=7.32 (1H, s), 7.25-7.18 (2H, m), 7.13 (1H, s), 7.12-7.10 (1H, d), 7.02-7.01 (1H, d), 6.79-6.77 (1H, d), 4.98-4.95 (1H, m), 4.65-4.64 (2H, d), 3.48 (2H, s), 3.48-3.43 (1H, m), 3.28-3.23 (1H, dd), 3.13-3.09 (1H, dd), 2.98-2.93 (1H, dd), 2.77-2.72 (1H, dd), 1.23-1.21 (3H, d), 0.86 (9H, s), 0.06 (3H, s), −0.13 (3H, s) ppm. LRMS (electrospray): m/z [M+H]+ 474, [M+Na]+ 496, [M−H]− 472. CHN analysis: found C, 64.15%; H, 8.25%; N, 2.84%. C26H39NO5Si+0.7H2O requires C 64.22%, H 8.37%, N 2.88%.
Provenance & Evidence
| DOI | 10.6084/m9.figshare.5104873.v1 |
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| Patent number | US07629358B2 |
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| Source dataset | uspto-grants-2009_12 |
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| ORD ID | ord-1783efed3c7b45d498455c30a94340af |
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| Source note | uspto-grants-2009_12 |
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