HRID1882237

反应详情

EQUATION

反应方程式

HRID 1882237 的结构方程式

PROCEDURE

实验过程

The title compound was prepared in 65% yield from Compound 131 according to the procedure outlined in the preparation of Compound 81. MS (ES) [m+H] calc'd for C22H20N2O4S, 409; found 409.